Respuesta :
ok, so
a(b-c)=ab-ac
9 is close to 10 so
828(9)=
828(10-1)=
828(10)-828(1)=
8280-828=
7000+1280-828=
7000+452=
7452
a(b-c)=ab-ac
9 is close to 10 so
828(9)=
828(10-1)=
828(10)-828(1)=
8280-828=
7000+1280-828=
7000+452=
7452
Answer:
First, write 828 as a sum of 800 + 20 + 8. Next, multiply each number by 9. Add the products to get 7,452.
Step-by-step explanation: