Respuesta :
Answer: A. 41.7%
Step-by-step explanation:
Let V denote the event of students play volley ball and B denote the event students play Basketball.
Given : The probability of students play volleyball P(V)= 12% = 0.12
The probability of students play volleyball and basketball P(V∩B)= 5% = 0.05
Now, the probability that a student plays basketball given that he or she plays volleyball is given by :-
[tex]\text{P(BlV)}=\frac{P(V\cap B)}{P(V)}\\\\=\frac{0.05}{0.12}=0.416666666667\approx0.417[/tex]
In percent,
[tex]\text{P(B l V)}=0.417\times100=41.7\%[/tex]