a map has a scale of 2 in : 6 mi if clayton and centerville are 10 in apart on the map then how far apart are the real cities

Respuesta :

I"m pretty sure they would be 60 mi apart

The distance in real between Clayton and Centerville when they are 10 in apart on the map is 30 miles.

What is the scale ratio?

The scale ratio of a model is the proportionate ratio of one of the model's linear dimensions to the equivalent characters in the original.

The scale ratio that is given to us is 2in:6mi, therefore, two inches on the map is equal to 6 miles in real, the ratio can be further reduced as,

[tex]\rm Scale\ ratio = \dfrac{2\ in}{6\ mi} = \dfrac{1\ in}{3\ mi}[/tex]

Now, as it is given that Clayton and Centerville are 10 in apart on the map, therefore, the distance between them in reality is,

[tex]\rm \dfrac{Map}{Real}=\dfrac{1\ in}{3\ mi}\\\\\\\dfrac{10\ in}{Real}=\dfrac{1\ in}{3\ mi}\\\\\\Real = \dfrac{10 \times 3}{1} = 30\ mi[/tex]

Hence, the distance in real between Clayton and Centerville when they are 10 in apart on the map is 30 miles.

Learn more about Scale Ratio:

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