A 1250 kg car is stopped at a traffic light. A 3550 kg truck moving at 8.33 m/s hits the car from behind If bumpers lock,how fast will the two vehicles move?

The momentum can be defined by the product of the maas and velocity. The final velocity of the trucks after the collision is 6.6 m/s.

From the law of conservation:

[tex]m_1v_1 +m_2v_2 = (m_1+m_2)v_f[/tex]

Where,

[tex]m_1[/tex]= mass of 1st truck = 1250 kg

[tex]m_2[/tex] - mass of second truck = 3550 kg

[tex]v_1[/tex] - velocity of the first truck = 0 m\s

[tex]v_2[/tex] - velocity of the second truck = 8.33 m/s

[tex]v_f[/tex] - final velocity after collision

Put the values in the formula,

[tex]1250 \times 0+(1350 \times 8.33 ) = (1250+1350 )v_f \\\\v_f = 6.6\rm \ m/s[/tex]

Therefore, the final velocity of the trucks after the collision is 6.6 m/s.

Learn more about the law of conservation:

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