Which strategy best explains how to solve this problem?

George entered his frog in a jumping contest. The frog jumped 2 feet the first jump. On the second jump, the frog jumped twice as far (4 feet). Each time the frog jumped, the jump doubled in length from its previous jump.

How far did the frog jump on the 5th jump?

A.
Make a table.

In the first row, write 1st jump - 2 ft. In the next row, write 2nd jump - 2 ft. In the 3rd row, write 3rd jump - 2 ft. Continue this pattern until you get to the 5th jump. Then add the numbers in the right column to find the number of feet the frog jumped on the 5th jump.

B.
Draw a diagram.

Draw a line and label it 2 ft. Draw a line twice as long and label it 4 ft. Do this three more times. Keep doubling the distance each time to find how far the frog jumped on the 5th jump.

C.
Write a number sentence.

(2 × 5) + 2 + 4 = x
Multiply 2 inches by the 5th jump, then add the distances from the first and second jump.

please need help

Respuesta :

The jumps in order would be, 2, 4, 8, 16, 64. So,
A should be easy enough for you if not comment and I will explain more.
B would be, --, (2ft), ----, (4ft), --------, (8ft), ----------------, (16ft), --------------------------------, (64ft). 
C:   (2 × 5) + 2 + 4 = x. So first you would do the parenthesis, which would then make it,  10+ 2 + 4 = x, then you would add all of the rest separately, which would be,  8+ 4 = x, then  12 = x. So you would eventually get 12 as the answer.
Write a number sentence or creat a table a graph would work too