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Prove that the angle bisectors of a rhombus are concurrent. Then prove that the point where the angle bisectors intersect is equidistant from all sides of the rhombus.

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MissPhiladelphia
All of the given choices are quadrilaterals. They only differ on the number of their parallel sides. A square has 2 parallel sides and all of its sides are equal or the same. A rhombus has 2 parallel sides and all of its sides are equal or only two of its sides are equal. 

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