Respuesta :

to find the sum:

2(3t-4) - (t^2 + 2) - 4t(t-1)

6t - 8 - t^2 - 2 - 4t^2 + 4

6t - 8 - 5t^2  + 2

-5t^2 + 6t - 6

by the sum of roots and product of roots formulae

ax^2 + bx + c

x + y  = [tex] \frac{-6}{-5} [/tex]

x + y = [tex] \frac{6}{5} [/tex]

xy = [tex] \frac{-6}{-5} [/tex]

xy = [tex] \frac{6}{5} [/tex]

x - y =