Respuesta :

4[2a+b]/c[b+2a] = 4/c.
[tex] \frac{8a+4b}{bc+2ac} [/tex]
this when factorised gives[tex] \frac{4(2a+b)}{c(2a+b)} [/tex]
2a+b on the numerator cancels 2a+b on the denominator
it will give[tex] \frac{4}{c} [/tex]*1
[tex] \frac{4}{c} [/tex]

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