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an airplane travels down a runway for 4.0 seconds with an acceleration of 9.0m/s. what is its change in velocity during this time?

Respuesta :

a=9m/s^2, u=0, t=4 secs
by the equations of motion
a = [tex] \frac{v-u}{t} [/tex]
9 = [tex] \frac{v}{4} [/tex]
∴v = 36m/s

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