Respuesta :
If the perimeter of paralleloram ABCD is AB + BC + CD + DA = 10 cm
and AB = DC and AD = BC then AB + AD = 5 cm
Or perimeter of triangle ABD is 8 cm then AB + AD + BD = 8 cm
then BD = AB + AD + BD - AB - AD = 8 - 5 = 3
and AB = DC and AD = BC then AB + AD = 5 cm
Or perimeter of triangle ABD is 8 cm then AB + AD + BD = 8 cm
then BD = AB + AD + BD - AB - AD = 8 - 5 = 3
The length of diagonal BD is 3.
We have given that the perimeter of parallelogram ABCD is
AB + BC + CD + DA = 10 cm
We have to calculate length of diagonal BD
And we know that the perimeter of triangle ABD is 8 cm.
and
AB = DC and AD = BC then AB + AD = 5 cm
Or perimeter of triangle ABD is 8 cm then
What is the perimeter of the tingle ABD?
AB + AD + BD=Perimeter
Therefore,
AB + AD + BD = 8 cm
BD = AB + AD + BD - AB - AD = 8 - 5 = 3
Therefore we get
The length of diagonal BD is 3.
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