Respuesta :

S=1/2at^2
2s=at^2
2s/a=t^2
T=sqaure root of 2s/a

Explanation:

It is given by :

[tex]s=\dfrac{1}{2}at^2[/tex]..... (1)

Where

s = distance covered

a = acceleration of an object

t = time taken

We need to manipulate given equation to find the value of t. On cross multiplication to both side of equation (1) we get:

[tex]2s=at^2[/tex]

Dividing both side of above equation by a we get :

[tex]t^2=\dfrac{2s}{a}[/tex]

Taking square root of above equation we get :

[tex]t=\sqrt{\dfrac{2s}{a}}[/tex]

So, the value of t is, [tex]t=\sqrt{\dfrac{2s}{a}}[/tex]. Hence, this is the required solution.