bgb1432
bgb1432
09-02-2017
Mathematics
contestada
How do you simplify csc(x)sec(x)-tan(x)
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LammettHash
LammettHash
09-02-2017
[tex]\csc x\sec x-\tan x=\dfrac1{\sin x\cos x}-\dfrac{\sin x}{\cos x}=\dfrac1{\sin x\cos x}-\dfrac{\sin^2x}{\sin x\cos x}=\dfrac{1-\sin^2x}{\sin x\cos x}=\dfrac{\cos^2x}{\sin x\cos x}=\dfrac{\cos x}{\sin x}=\cot x[/tex]
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