Respuesta :
If the image that accompanies this problem is the same as that in my attachment, then the area of the new circle is:
Given data in the attachment:
GY = 10 cm
YX = 16 cm
A = πr²
A = π (26cm)²
A = 676cm² π
Given data in the attachment:
GY = 10 cm
YX = 16 cm
A = πr²
A = π (26cm)²
A = 676cm² π
