We get the dimensions of the park as length = 75 feet and width = 20 feet.
We are given that:
A yard has a perimeter of 190 feet.
Also, four times the length of the yard equals 15 times the width.
Now,
Let the length of the yard be x.
ATQ, we get the width of the yard as:
15 width = 4 x
Width = 4 / 15 x
Perimeter = 2 ( l + b )
190 = 2( x + 4 / 15 x )
95 = 19 x / 15
19 x = 95 × 15
19 x = 1425
x = 1425 / 19
x = 75 feet.
Length = 75 feet
Width = 4 / 15 x = 20 feet.
Therefore, we get the dimensions of the park as length = 75 feet and width = 20 feet.
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