The equation of the circle centered at the origin and passing through the point (0,11) will be x² + y² = 121.
A circle can be characterized by its center's location and its radius's length.
Let the center of the considered circle be at the (h,k) coordinate.
Let the radius of the circle be 'r' units.
Then, the equation of that circle would be:
(x - h)² + (y - k)² = r²
The equation of the circle centered at the origin will be
x² + y² = r²
Then the equation is passing through the point (0,11). Then we have
r² = 0² + 11²
r² = 121
r = 11
Then the equation will be
x² + y² = 121
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