Spacecraft will take around 49 minute and 92 second to coast from perigee to the apogee.
We use Kepler's third law for which the time period is defined as
[tex]T = 2 \pi \sqrt[]{\frac{a^{3} }{GM} }[/tex]
The Prague's altitude is the shortest distance between the earth's surface and satellite.
The average distance of the perigee and apogee of satellite can be defined as
a = R + [tex]\frac{r_{1} +r_{2} }{2}[/tex]
R is the radius of earth (6374.1km)
r1 is the lower orbit. (500km)
r2 is the higher orbit.(900km)
Using the values in above equation we get:
6374.1+ (500+ 900)/2
a = 7078.1 km
Time taken to fly from perigee to apogee equals to the half of the orbital speed so
t = T/2
[tex]t = \pi \sqrt[]{\frac{a^{3} }{GM} }[/tex]
by using the values we get-
= √[(7078.1)³/6.67 ×10⁻¹¹ × 6×10²⁴]
= 295573.94 * 10⁻²
= 2995.73s
t = 49 mint 92 sec
It will take around 49 minute and 92 second to coast from perigee to the apogee.
To know more about perigee ang apogee :
https://brainly.com/question/28538480
#SPJ4
