Choose the equation below whose axis of symmetry is x = 0.

y = x2 + 2x
y = x2 − 16x + 58
y = x2 + 2
y = x2 − 4x + 2

Respuesta :

i think the answer would be y =x2+2
frika

The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The x-coordinate of the vertex of the parabola [tex]y=ax^2+bx+c[/tex] can be found as

[tex]x_v=-\dfrac{b}{2a}.[/tex]

The equation x=0 represents the y-axis, therefore, parabola should be symmetric about the y-axis. This means that parabola vertex is placed on the y-axis. If parabola vertex is placed on the y-axis, then [tex]x_v=0[/tex] and

[tex]-\dfrac{b}{2a}=0\Rightarrow b=0.[/tex]

Only third parabola has b=0, then

correct choice is C.