Respuesta :

[tex]\bf \textit{the graph starts at }0\textit{ and goes to }\pi \\\\ A=\frac{\pi }{6}\textit{ now, B is away from }\pi \textit{ 1A} \\\\ \textit{since A and B have a same y-value,}\\ \textit{and the graph is symmetric, thus} \\\\ B=\pi -\frac{\pi }{6}[/tex]
the other person is correct