56 meters have been determined as the distance traveled.
s-displacement, u-initial velocity, v-final velocity, a-acceleration, and t-time variables are equal to v=u + at and v2 = u2 + 2ass, respectively.
The motorcycle's values are as follows:
u= 0m/s
v=28m/s
t=4s
a=??
s=??
v=u +at
28= 0 + 4a
4a=28
a= 7m/s2
As a result, the typical acceleration is 7 m/s2.
displacement u2+2as, v2=s
28^2= 0^2+ (2x7s)
784= 14s
s= 784/14
s= 56
Therefore, the journey's distance was 56 meters.
Learn more about distance here-
https://brainly.com/question/15172156
#SPJ4
