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A ball is thrown from an initial height of 6 feet with an initial upward velocity of 40 fVs. The ball's height h (in feet) after / seconds is given by the following.
h=6+401-16r²
Find all values off for which the ball's height is 28 feet.
Round your answer(s) to the nearest hundredth.

Respuesta :

The value for which the ball's height is 28 feet are 0.817sec and 1.683sec using quadratic equations.

What is a quadratic equation?

  • In algebra, a quadratic equation( from Latin quadratus' forecourt') is any equation that can be rearranged in standard form as

ax^2 + bx + c = 0

where x represents an unknown, and a, b, and c represent known figures, where a ≠ 0. is still, not quadratic, as there's no ax^2 term,( If a = 0( and b ≠ 0) also the equation is direct.)

  • The figures a, b, and c are the portions of the equation and may be distinguished by calling them, independently, the quadratic measure, the direct measure, and the constant or free term.
  • The values of x that satisfy the equation are called results of the equation, and the roots or bottoms of the expression on its left-hand side.
  • A quadratic equation has at most two solutions.

Given,

h(0)=6 ft (six)

v(0)=40 ft/sec (fourty)

h(t)=6+40t-16t2 (equation)

for h=28 ft(twenty eight)

28=6+40t-16t2 (equation)

or 16t2 - 40t + 22 = 0 (equation)

or 8t2 - 20t + 11= 0(equation)

on solving the quadratic equation

t=0.817sec and 1.683sec (answer)

Learn more about quadratic equations here: https://brainly.com/question/1214333

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