The percent error in the volume measurement was 0.238 %.
d(water) = 0.99738 g/ml; density of the water at 24°C
V(water) = 10.00 m; volume of the water sample
m(water) = d(water) × V(water)
m(water) = 0.99738 g/ml × 10.00 ml
m(water) = 9.9738 g; mass of the water sample
error = (9.9738 g - 9.95 g) ÷ 9.9738 g · 100%
error = 0.238 %
The percent error is an error between an observed value and the true value of a measurement.
In this problem, an observed value is 9.95 grams and the true value of a measurement is 9.9738 grams.
More about volume: brainly.com/question/4936894
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