A container holds 1 mole of helium gas. The volume of the container is 2 liters and the pressure inside the container is 105.0 kPa. If the volume of the container is decreased to 1.5 liters, what will be the new pressure inside the container?
1 mole of helium gas the volume of one mole of helium gas is V=22.4L (this is the so-called molar volume of any gas) so the volume initial is V1= V+ Vcontainer =22.4L + 2L=24.4L according to boyles Law P1 /V1 = P2 /V2 and 1kPa = 0.009 atm 105.0 kPa= 0.94 atm so P2 = V2 x P1 / V1= 1.5 x 0.95 / 24.4 = 0.05 atm
