The absolute value equation is:
|M - 430g| = 20g
And the solutions are M = 410g and M = 450g
b) No, the mass is not acceptable.
We know that the recomended mass is 0.43kg, with an accepted error of 20 grams.
Where:
0.43kg = 0.43*1000g = 430g
Then the minimum mass accepted is: 430g - 20g = 410g
The maximum mass accepted is: 430g + 20g = 450g
These are the solutions, and the absolute value equation is, if M is the mass:
|M - 430g| = 20g
b) If the ball has a mass of 423g it is in the accepted range, if now it loses 0.016kg:
0.016kg = 0.016*1000g = 16g
The new mass is:
423g - 16g = 407g
This is smaller than the minimum accepted mass, then this mass is not acceptable.
If you want to learn more about absolute value equations:
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