The 3 consecutive odd integers are -3, -5 and -7
Let the 3 consecutive odd integers be 2x-1, 2x+1 and 2x+3
If the sum of 2 times the first and the last term is equal to 5 times the middle integer, then;
2(2x-1)+2x+3 = 5(2x+1)
Expand
4x-2 + 2x +3 = 10x+5
6x +1 = 10x + 5
6x - 10x = 5 - 1
-4x = 4
x = -1
Determine the numbers
First number = 2(-1) - 1 = -3
Second number = -5
Third number = -7
Hence the 3 consecutive odd integers are -3, -5 and -7
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