As given the sum of squares of three consecutive integers, four digits which never occur in the ones place are 1,3,6,8.
As given,
Let x -1 , x , x +1 are three consecutive integers.
Sum of the squares of three consecutive integers
= (x -1)² +x² + (x+1)²
= x² -2x +1 +x² +x² +2x +1
=3x² +2
Now substitute x = 0,1,2,3,4,5,6,7,8,9
Sum = 2, 5,14,29, 50, 77, 110, 149, 194, 245
Four digit never occur at ones place = 1,3,6,8
Therefore, as given the sum of squares of three consecutive integers, four digits which never occur in the ones place are 1,3,6,8.
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