The plant efficiency will be 75%.
We have a engineer in a Electric - Generation Station.
We have to determine the maximum efficiency plant will ever achieve.
The maximum efficiency the plant will achieve is defined as -
η(max) = 1 - [tex]$\frac{T_{min} }{T_{max} }[/tex]
Now -
T(minimum) = Temperature of Cooling water = 300 K
T(maximum) = Temperature of boiler = 1200 K
Therefore -
The maximum efficiency will be -
η(max) = 1 - [tex]\frac{300}{1200}[/tex]
η(max) = 1 - [tex]\frac{1}{4}[/tex]
η(max) = 3/4
Percentage efficiency = [tex]\frac{3}{4} \times 100\\[/tex] = 3 x 25 = 75%
Hence, the plant efficiency will be 75%.
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[ The given question is incomplete. The complete question is given below -
You are an engineer in an electric-generation station. You know that the flames in the boiler reach a temperature of 1200 K and that cooling water at 300 K is available from a nearby river. What is the maximum efficiency your plant will ever achieve? ]