a stunt man drops from a building and falls 15m down onto a giant air mattress a) How much time does it take for the stunt man to hit the air mattress.
B.) What is his velocity as he slams into the mattress (# and direction)

please draw a sketch also!!

Respuesta :

The time taken is √3 s and the velocity with he lands is 17.3 m/s.

What is the time taken?

In this case, we have to use the equations of kinematics as it has to do with motion under gravity. We know that;

h = ut + 1/2gt^2

h = height

u = initial velocity

g = acceleration due to gravity

t = time taken

Given that u = 0 m/s because the object was dropped from a height.

h = 1/2gt^2

t = √2h/g

t = √2 * 15/10

t = √3 s

The velocity with which he falls is obtained from;

v = u + gt

v = gt

v = 10 m/s^2 * √3 s

v = 17.3 m/s

Learn more about kinematics:https://brainly.com/question/14355103

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