The time taken is √3 s and the velocity with he lands is 17.3 m/s.
In this case, we have to use the equations of kinematics as it has to do with motion under gravity. We know that;
h = ut + 1/2gt^2
h = height
u = initial velocity
g = acceleration due to gravity
t = time taken
Given that u = 0 m/s because the object was dropped from a height.
h = 1/2gt^2
t = √2h/g
t = √2 * 15/10
t = √3 s
The velocity with which he falls is obtained from;
v = u + gt
v = gt
v = 10 m/s^2 * √3 s
v = 17.3 m/s
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