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train cars are coupled together by being bumped into one another. suppose two loaded train cars are moving toward one another, the first having a mass of 168000 kg and a velocity of 0.291 m/s, and the second having a mass of 117000 kg and a velocity of -0.128 m/s. (the minus indicates direction of motion.) what is their final velocity?

Respuesta :

Their final velocity would be 0.118 m/s

Calculation

M1= 168000kg, V1= 0.291 m/s

M2= 117000kg, V2 = 0.128 m/s

According to conservation of momentum,

M1V1 + M2V2 = V(M1+M2)

⇒V = [tex]\frac{168000 * 0.291-117000*0.128}{168000+117000}[/tex]

=[tex]\frac{48888-14976}{285000}[/tex]

=0.118 m/s

Thus, the trains will finally get to the velocity of 0.118 m/s

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