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In the sport of billiards, event organizers often remove one of the rails on a pool table to allow players to measure the speed of their break shots (the opening shot of a game in which the player strikes a ball with his pool cue).
The top of a pool table is a height ℎ=2.75 ft from the floor. If a player's ball lands a distance =16.50 ft from the table edge, what is her break shot speed 0?

In the sport of billiards event organizers often remove one of the rails on a pool table to allow players to measure the speed of their break shots the opening class=

Respuesta :

onyebuchinnaji

The break shot speed of the player is determined as 96.5 ft/s.

Time of motion of the player

use the following kinematic equation to determine the time of motion of the player.

h = vt + ¹/₂gt²

h = 0 + ¹/₂gt²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 2.75/32.17)

t = 0.171 s

break shot speed

vx = x/t

vx = 16.5 ft / 0.171 s

vx = 96.5 ft/s

Thus, the break shot speed of the player is determined as 96.5 ft/s.

Learn more about break shot speed here: https://brainly.com/question/8852339

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