The angle in degrees between the two planes is approximately 159.460°.
The equation of the plane, whose form is a · x + b · y + c · z = d is equivalent to this vectorial form (a, b, c) • (x, y, z) = d, where (a, b, c) is the vector of coefficients. The angle between the two planes:
θ = cos⁻¹ [[(a₁, b₁, c₁) • (a₂, b₂, c₂)] / [||(a₁, b₁, c₁)|| · ||(a₁, b₁, c₁)||]]
If we know that (a₁, b₁, c₁) = (1, - 10, - 8) and (a₂, b₂, c₂) = (2, 5, 8), then the angle between the two planes is:
θ = cos⁻¹ [[(1, - 10, - 8) • (2, 5, 8)] / [√165 · √93]]
θ = cos⁻¹ [(-2 - 50 - 64) / √15345]
θ = cos⁻¹ (- 116 / √15345)
θ ≈ 159.460°
The angle in degrees between the two planes is approximately 159.460°.
To learn more on equations of planes: https://brainly.com/question/27190150
#SPJ1
