Answer:
12 and 14
Step-by-step explanation:
You want two consecutive even integers such that the lesser is five more than half the greater.
Let x represent the lesser of the integers. Then x+2 is the greater, and we can write the given relation as ...
x = (x+2)/2 +5 . . . . . lesser is 5 more than half the greater
Multiplying by 2 gives ...
2x = x +2 +10
x = 12 . . . . . . . . subtract x
x+2 = 14
The two integers are 12 and 14.
