Rays DA and DC are perpendicular. Point B lies in the interior of {angle]ADC. If m[angle]ADB = (3a + 10) degrees and m[angle]BDC = 13a degrees, find a, m[angle]ADB, and m[angle]BDC

Respuesta :

Applying the definition of the angle formed by perpendicular lines, the measures are:

a = 5

m<ADB = 25°

m<BDC = 65°

What is the Angle Formed by Perpendicular Lines?

When two lines intersect perpendicularly at a point, they form a right angle, which is equal to 90 degrees.

Thus, angle ADC is a right angle. Therefore, angles ADB and BDC are complementary angles. This means that:

m<ADB + m<BDC = 90°

Substitute

3a + 10 + 13a = 90

16a + 10 = 90

16a = 90 - 10

16a = 80

16a/16 = 80/16

a = 5

m<ADB = (3a + 10) = 3(5) + 10 = 25°

m<BDC = 13a = 13(5) = 65°

Thus, applying the definition of the angle formed by perpendicular lines, the measures are:

a = 5

m<ADB = 25°

m<BDC = 65°

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