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I'm having trouble with picking the correct equations for this. Some ways equal 12.4 N-m, but that's wrong. 24.8 N-m is also wrong. I have 62sin60 and 62cos60, and the perpendicular should be 200mm.

Im having trouble with picking the correct equations for this Some ways equal 124 Nm but thats wrong 248 Nm is also wrong I have 62sin60 and 62cos60 and the per class=

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The couple of the moment of the two forces is 3.82 N.m

What is the Moment of the Couple?

We are given;

Force applied at A; F_a = 62 N

Force applied at C; F_c = 62 N

AB = BC = 200 mm = 0.2 m

Horizontal component of  F_a is; F_ax = 62 cos 50

Vertical component of  F_a is; F_ay = 62 sin 50

Horizontal component of  F_c is; F_cx = 62 cos 50

Vertical component of  F_c is; F_cy = 62 sin 50

Taking moments about point C gives;

M_c = F_ay * AB - F_ax * BC

M_c = (62 sin 50 * 0.2) - (62 cos 50 * 0.2)

M_c = 23.75 - 19.93

M_c = 3.82 N.m

Thus, the couple of the moment of the two forces is 3.82 N.m

Read more about Moment of Couple at; https://brainly.com/question/24551104

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