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Abby throws a ball straight up and times it. She sees that the ball goes by the top of a flagpole after 0.50 s and reaches the level of the top of the pole after a total elapsed time of 4.1 s. What was the speed of the ball at launch? Neglect air resistance

Respuesta :

The speed of the ball at launch is 23m/s.

After 0.5 seconds, the ball initially passed the pole.

Then it will again reach the top of the pole after 4.1 seconds.

Consequently, the ball's travel time above the pole is

Δt  = 4.1 - 0.5 = 3.6sec

Now the time it will take to reach the highest point from the top of the pole is given as t = Δt/2 = 1.8sec.

Now the total time to reach the top from the bottom is given as 2.3sec.

After 0.5 seconds, the ball initially passed the pole.

Consequently, the ball's travel time above the pole is

[tex]v_{f} - v_{i} = at[/tex]

[tex]v_{i}=22.54m/s[/tex]

also the speed after 0.5 s is

[tex]v_{f} = 17.64m/s[/tex]

So, the speed of the ball at launch is 23m/s.

Learn more about speed here;

https://brainly.com/question/93357

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