[tex]\pink{★}[/tex]Height of the pole = BC
[tex]\pink{★}[/tex]Distance from the foot of the pole and the point = AB = 7 m
[tex]\pink{★}[/tex]length of the wire of one side = AC= 25m
[tex]\pink{★} [/tex]∆ ABC is a right angled triangle ∠B = 90°
By Pythagoras theorem :
[tex]\tt{AC^2 = BC^2+ AB^2}[/tex]
[tex]\tt{25^2 = h^2+7^2}[/tex]
[tex]\tt{625 = h^2+49}[/tex]
[tex]\tt{h^2 =625-49}[/tex]
[tex]\tt{h^2 = 576}[/tex]
[tex]\tt{h = \sqrt{576}}[/tex]
[tex]\tt{h= 24m}[/tex]
The height of pole is 24 m .
