The vertical distance of helicopter from the ground is equal to 2000 / 3 m.
Let the distance between the two planes A and B be x.
In △ ADC, we get that:
tan 60° = 2000 / y
√3 = 2000 / y ...(1)
Now, in △ BCD, we get that:
tan 30° = 2000 - x / y
1 / √3 = (2000 - x) / y ... (2)
Divide (1) from (2):
3 = 2000 / (2000 - x)
6000 - 3 x = 2000
3 x = 6000 - 2000
3 x = 4000
x = 4000 / 3
(2000 - x) = 2000 - 4000/3 = 2000 / 3
Therefore, the vertical distance of helicopter from the ground is equal to 2000 / 3 m.
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