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question 4 suppose the fraction of high school students who can drive is 15% and the fraction of college students who can drive is 23%. if one-fifth of the students are college students and the rest are high school students, what is the probability that a student who can drive is a college student? select the correct probability.

Respuesta :

The probability that a student who can drive is a college student is 0.2771 or 27.7%

It will be sooved using Baye's theorem -

P(college) = P(C) / 1/5 = 0.2

P(high school students) = P(H) = 4/5 = 0.8

P(college drives) = 0.23

P(high school drives) = 0.15

We have to find, probability that a student who drives is a college student.

That is, we have to find P(C/D).

P(C/D) = P(C ∩ S)/P(S)

Since P(C ∩ S) is an independent event.

P(C ∩ S) = P(C) × P(S)

P(C ∩ S) = 0.2 × 0.23

= 0.046

Using bayes's theorem, we will get

P(C/D) = 0.2771 or 27.7%

To learn more about baye's theorem from given link

https://brainly.com/question/4616547

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