3) Two particles are travelling along a straight line AB of length 20m.
At the same instant one particle starts from rest at A and travels
towards B with a constant acceleration of 2 ms72 and the other
particle starts from rest at B and travels towards A with a constant
acceleration of 5 ms2, find how far from A the particles collide.

Respuesta :

At distance of 40/7 m from A the particles will collide.

Let particles collide at C

And let distance AC = x and BC = y

then, x+y = 20

As the equation used for distance required here is: s= ut +1/2 a[tex]t^{2}[/tex] and  here u=0

Then, 1/2 (2)[tex]t^{2}[/tex]  +1/2 (5)[tex]t^{2}[/tex]  =20  

7/2[tex]t^{2}[/tex]  =20

[tex]t^{2}[/tex] = 40/7

Now

x= 1/2 (2)[tex]t^{2}[/tex] = 40/7 m

Therefore, at distance of 40/7 m from A the particles will collide.

Learn more about distance here;

https://brainly.com/question/15172156

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