At distance of 40/7 m from A the particles will collide.
Let particles collide at C
And let distance AC = x and BC = y
then, x+y = 20
As the equation used for distance required here is: s= ut +1/2 a[tex]t^{2}[/tex] and here u=0
Then, 1/2 (2)[tex]t^{2}[/tex] +1/2 (5)[tex]t^{2}[/tex] =20
7/2[tex]t^{2}[/tex] =20
[tex]t^{2}[/tex] = 40/7
Now
x= 1/2 (2)[tex]t^{2}[/tex] = 40/7 m
Therefore, at distance of 40/7 m from A the particles will collide.
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