Activity would be expected for a 25.3 mg sample of carbon-14 is 25.296
Here given data is Carbon-14 has a half-life of 5730 yrs and expected for a 25.3 mg sample of carbon-14 =?
So here half life of Carbon-14 is t1/2=5730 yrs
This means that 5730 yrs the initial amount of carbon-14 will be halved
The radioactive constant is λ=ln2/t1/2 = ln2/5730=0.000121
The fundamental decay equation is m=m0e⁻λt
Initial amount of carbon-14 is m0=25.3
Therefore, 25.3×e⁰⁰⁰⁰¹²¹=25.296
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