acceleration is sometimes expressed in multiples of g, where is the acceleration due to the earth's gravity. in a car crash, the car's velocity may go from 20 m/s to 0 m/s in 0.067 s how many g's are experienced, on average, by the driver? (answer with just the number)

Respuesta :

The g’s experienced by the driver will be 30.45 g.

The above is a case of uniformly accelerated motion.

So we have to use one of the following equations to solve it,

v = u + at

v^2 - u^2 = 2as

s = ut + 1/2t^2

As we are given the final velocity, initial velocity and the time, therefore the first equation is appropriate.

v = u+ at

Putting v = 0 m/s

u = 20 m/s

t = 0.067 s

0 = 20 + at

The acceleration comes out to be 298.50 m/s^2.

As g = 9.8 m/s^2, dividing the value of acceleration by 9.8 will give the value of g experienced by the driver.

A = 298.50/9.8 = 30.45g m/s^2.

Hence, The g’s experienced by the driver will be 30.45 g.

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