Respuesta :
Height above the top of Tom's window the ball was dropped= 1.31m
Given that,
The height of window (s) = 1.50m
Time(t) = 0.240s
We have to find the height, and for this, we have to find the velocity using the equation of motion:
s = ut + 1/2 g[tex]t^{2}[/tex]
By putting the value of h and t in the equation
1.50 = u × 0.240 + 1/2 × 9.8 × [tex]0.240^{2}[/tex]
1.50 = u × 0.240 + 0.28224
u = (1.50 - 0.28224) / 0.240
u= 1.21776 / 0.240
u= 5.074
Now we have to calculate height by using the formula
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2gh
By putting the value of u and v we get
[tex]5.074^{2}[/tex] = 0 + 2 × 9.8 × h
h = [tex](5.074)^{2}[/tex]/ 2 × 9.8
h = 1.31 m
Therefore the height is 1.31 m above the window.
To know more about the equation of motion refer to the link given below:
https://brainly.com/question/18152494
#SPJ4
The complete question is:
A ball is dropped from an upper floor, some unknown distance above Tom's apartment. As he looks out of his window, which is 1..50 m tall, Tom observes that it takes the ball 0.240 s to traverse the length of the window. Determine how high ℎ above the top of Tom's window the ball was dropped. Ignore the effects of air resistance.
