The ordered pairs of the solutions for this system of equations is (-2,11) and (-1,6)
Two integers written in a certain order make up an ordered pair. As a result, we may define an ordered pair as a pair of components that appear in brackets and in a specific order.
These equations are composed of a line and a parabola. The intersection points between them must be located:
[tex]y=x^2-2x+3[/tex]
y=-5x+1
Thus,
[tex]x^2-2x+3=-5x+1[/tex]
[tex]x^2-2x+5x+3-1=0[/tex]
[tex]x^2+3x+2=0[/tex]
[tex]x^2+x+2x+2=0[/tex]
[tex]x(x+1)+2(x+1)=0[/tex]
x+2=0, x=-2
x+1=0, x=-1
Since the quadratic expression may be factored out, the following x-values represent the system's solution:
x=-2 and x=-1
Now, we may obtain the corresponding y values using either of the system's original equations. We decide to use a linear equation as an illustration:
When x =-2,
y=11
x=-1,
y=6
Thus the two points solution us (-2,11) and (-1,6)
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