The empirical formula for the compound containing 42.88% carbon and 57.1% oxygen by mass is Carbon Monoxide (CO).
To find the empirical formula for 42.8% carbon (C) and 57.1% oxygen (O)
First, find the molar mass of each component-
C = 12.010, O = 15.999
Converting to the moles :
C = 3.563, O = 3.568
Finding smallest mole value :
C = 3.563
Dividing all components by smallest value :
C = 1, O = 1.001
By rounding off -
C = 1, O = 1
Combining to get empirical formula : CO
Now, multiplying all by 1 ( molar mass of empirical formula/molar mass of sample = 28.01 / 28.034 ) to get molecular formula : CO
Since multiplied by 1, Therefore, the empirical formula and molecular formula are same.
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