Respuesta :
If 34.4 g of pentane (C₅H₁₂) are burnt in excess oxygen, 50.7 g of H₂O will be produced.
The balanced chemical reaction when pentane is burned in excess oxygen is :
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O
It is a Combustion reaction.
From above balanced chemical reaction,
Molar ratio of pentane and H₂O is - 1 : 6
Given mass of pentane = 34.4 g
Molar mass of pentane = 72.1 g
Number of moles of pentane = Given Mass
Molar mass
Number of moles = 34.4 = 0.4 moles
72.1
Since, 1 mole of pentane produces 6 moles of H₂O
Therefore,
Moles of water produced by 0.47 moles of pentane,
= 0.4 x 6 = 2.8 moles
Mass of H₂O = Number of moles x molar mass
Mass of H₂O = 2.8 x 18.0 = 50.7 g
Therefore, mass of H₂O produced will be 50.7 grams.
To learn more about combustion reactions,
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