The answers would be for 2nd and 3rd composites are X3Z4 and X4Z3.
The given questions is incorrect, the question is that the first emulsion has the formula X2Z3. also what is the chemical formula for alternate and also the third emulsion?
According to the question,
Mass of X in first emulsion = 1.0 g
Mass of Z in first emulsion = 0.472 g
The chemical formula of first emulsion = X2Z3
This means1.0 g of X is over to 2 intelligencers of X
= > One operative of X = 0.5 g of X.
g of Z is similar to 3 intelligencers of Z< = > one operative of Z = 0.15733 g of X.
Now for the Alternate emulsion,
Mass of X = 1.0 g
intelligencers of X = 1.0/0.5 = 2
Mass of Z = 0.420 grams
Number of intelligencers of Z = 0.420/0.15733 = 2.6695 intelligencers
rate of intelligencers of X to Z = 22.6695 = 3 4
Empirical formula of alternate emulsion = X3Z4
Now for the third emulsion,
Mass of X = 1.0 g
Intelligencers of X = 1/0.5 = 2 intelligencers
Mass of Z = 0.236 grams
Number of intelligencers of Z = 0.236/0.15733 = 1.5 intelligencers
Rate of intelligencers of X to Z = 21.5 = 4 3
Empirical formula of third emulsion = X4Z3
To know more about empirical formula here :
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