three pure compounds are formed when 1.00-g samples of element x combine with, respectively, 0.472 g, 0.420 g , and 0.236 g of element z. the first compound has the formula x2z3.

Respuesta :

The answers would be for 2nd and 3rd composites are X3Z4 and X4Z3.

The given questions is incorrect, the question is that the first emulsion has the formula X2Z3. also what is the chemical formula for alternate and also the third emulsion?

According to the question,

Mass of X in first emulsion = 1.0 g

Mass of Z in first emulsion = 0.472 g

The chemical formula of first emulsion = X2Z3

This means1.0 g of X is over to 2 intelligencers of X

= > One operative of X = 0.5 g of X.

g of Z is similar to 3 intelligencers of Z< = > one operative of Z = 0.15733 g of X.

Now for the Alternate emulsion,

Mass of X = 1.0 g

intelligencers of X = 1.0/0.5 = 2

Mass of Z = 0.420 grams

Number of intelligencers of Z = 0.420/0.15733 = 2.6695 intelligencers

rate of intelligencers of X to Z = 22.6695 = 3 4

Empirical formula of alternate emulsion = X3Z4

Now for the third emulsion,

Mass of X = 1.0 g

Intelligencers of X = 1/0.5 = 2 intelligencers

Mass of Z = 0.236 grams

Number of intelligencers of Z = 0.236/0.15733 = 1.5 intelligencers

Rate of intelligencers of X to Z = 21.5 = 4 3

Empirical formula of third emulsion = X4Z3

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