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Solubility of a given compound is referred to a specific temperature and solvent. This means that you need some data or starting information.

In this case you can use the molar solubility of the silver chromate in water at 25.0 °C.

The molar solubility of silver chormate is 1.10 * 10 ^ -12 M.

This means 1.10 * 10 -12 mol of silver chromate per liter of solution.

Given that the concentration of the solution is so low the density of it is almost the same density of water, i.e. 1g/mL.

Then you have 1.10 - 10^-12 mol of silver chromate per 1000 g of solution

Now convert the moles of silver chromate in grams, using its molar mass.

Silver chromate is Ag2CrO4.

Molar mass of Ag2 CrO4 = 2*108g/mol +52g/mol + 4*16g/mol = 332 g/mol

1.10 * 10^-12 mol * 332 g/mol = 3.652 * 10^ -10 g.

That is the number of grams in 1000 grams of solution, then you need to multiply times 1000 to convert to 1,000,000 grams of solution =

3.652 * 10^-10 * 10^3 grams of Ag2CrO4 / 1,000,000 grams of solution = 3.652 * 10^-7 grams of Ag2CrO4 / 1,000,000 grams of solution =

Remember ppm is parts per million, then it is 3.652 * 10^ -7 ppm

Answer: 3.652 * 10^-7 ppm 

smarazazaidi

The solubility of silver chromate in parts per million 3.652 * 10^-7 ppm.

Further Explanation:

How to find:

Solubility of a given compound is alluded to a particular temperature and dissolvable. This implies you need a few information or beginning data.  

For this situation you can utilize the molar solvency of the silver chromate in water at 25.0 °C.  

The molar solvency of silver chormate is 1.10 * 10 ^ - 12 M.  

This implies 1.10 * 10 - 12 mol of silver chromate per liter of arrangement.  

Given that the centralization of the arrangement is so low its thickness is nearly a similar thickness of water, for example 1g/mL.  

At that point you have 1.10 - 10^-12 mol of silver chromate per 1000 g of arrangement  

Presently convert the moles of silver chromate in grams, utilizing its molar mass.  

Silver chromate is Ag2CrO4.  

Molar mass of Ag2 CrO4 = 2*108g/mol +52g/mol + 4*16g/mol = 332 g/mol  

1.10 * 10^-12 mol * 332 g/mol = 3.652 * 10^ - 10 g.  

That is the quantity of grams in 1000 grams of arrangement, at that point you have to increase times 1000 to change over to 1,000,000 grams of arrangement =  3.652 * 10^-10 * 10^3 grams of Ag2CrO4/1,000,000 grams of arrangement =3.652 * 10^-7 grams of Ag2CrO4/1,000,000 grams of arrangement .

Keep in mind ppm is parts per million, at that point it is 3.652 * 10^ - 7 ppm.  

Silver chromate:  

Silver chromate is a dark colored red monoclinic gem and is a substance forerunner to current photography. It tends to be framed by consolidating silver nitrate and potassium chromate or sodium chromate.

Subject: chemistry

Level: High School

Keywords: how to find, silver chromate.

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