contestada

a 26.9-g mass is suspended 1.79 cm above a nonconducting flat plate, directly above an embedded charge of q. a) if the mass has the same charge, q, how much must q be so that the mass levitates (just floats, neither rising nor falling)?

Respuesta :

For mass to levitate charge must be 9.692×10⁻⁸ C.

For mass to levitate,

mg=Fe ( Fe here refers to electrostatic force)

mg=(kq₁q₂/r²)

here q₁=q₂,

q²=(mgr²/k)

q²=( 26.9×10⁻³×9.81×(1.79×10⁻²)²)/9×10⁹

q²=93.947×10⁻¹⁶

q = 9.692×10⁻⁸ C

To learn more about charge, visit: https://brainly.com/question/14597668

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