The odds that a carton of eggs will have at least one cracked egg is 97.5 %
The question has to do with probability
Probability is the likelihood for an event to occur. It is given by P(event) = number of required outcomes/total number of possible outcomes.
Given that the probability that a carton of eggs taken from the cooler at a store will have at least one cracked egg is 2.5%. Let the probability of at least one cracked egg be P(egg ≤ 1) = 2.5% = 0.025
Now, since we require the probability of that a carton of eggs will have at least one cracked egg, that is the number of cracked is greater than 1.
Let the probability of cracked eggs greater than 1 be P(egg ≥ 1).
From the law of probability
P(egg ≤ 1) + P(egg ≥ 1) = 1
So, P(egg ≥ 1) = 1 - P(egg ≤ 1)
P(egg ≥ 1) = 1 - 0.025
P(egg ≥ 1) = 0.975
P(egg ≥ 1) = 0.975 × 100 %
P(egg ≥ 1) = 97.5 %
So, the odds that a carton of eggs will have at least one cracked egg is 97.5 %
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