The acceleration of the object is 5.3 cm/[tex]s^{2}[/tex] and is directed towards the negative x - axis.
We have an object moving with uniform acceleration along the + x axis.
We have to determine of the acceleration of object after 3.25 seconds.
According to the question -
initial velocity = u = 11 cm/s along +x axis.
Now, using the second equation of motion -
[tex]$S=ut +\frac{1}{2}at^{2}[/tex]
S = x(2) - x(1) = - 5 - 2.91 = - 7.91 = 7.91 cm along -x axis.
u = 11 cm/s
Substituting the values -
7.91 = 11 x 3.25 + 0.5 x 3.25 x 3.25 x a
7.91 = 35.75 + 5.3a
a = - 5.3 cm/[tex]s^{2}[/tex]
Hence, the acceleration of the object is 5.3 cm/[tex]s^{2}[/tex] and is directed towards the negative x - axis.
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