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If you double your driving speed, then the stopping distance will be four times the original.

What is the equation of motion?

Equations of motion are equations that describe a physical system's behavior in terms of its motion as a function of time. Equations of motion, The three equations of the motion are,

  1. v - u = at
  2. S = ut + 0.5(at²)
  3. v² - u² = 2as

where

S is the distance,

u is the initial velocity,

v is the final velocity,

t is the time,

a is the acceleration.

Given that the car is traveling at a speed and is needed to be stopped, therefore, the car will deaccelerate. Also, the final velocity of the car will become 0. Therefore, we can write,

v² - u² = 2as

Substitute the values,

  • Final velocity, v = 0
  • Initial velocity, u = u
  • Distance covered, s = s₁
  • Acceleration, a = -a

Therefore, we can write,

v² - u² = 2as₁

(0)² - u² = 2(-a)s₁

-u² = -2as₁

u² = 2as₁

s₁ = u² / 2a

Now, if you double your driving speed. Therefore, we can write,

v² - u² = 2as

Substitute the values,

  • Final velocity, v = 0
  • Initial velocity, u = 2u
  • Distance covered, s = s₂
  • Acceleration, a = -a

Therefore, we can write,

v² - u² = 2as₂

(0)² - (2u)² = 2(-a)s₂

-4u² = -2as₂

4u² = 2as₂

s₂ = 4u² / 2a

Since u²/2a is equal to s₁, therefore, we can write,

s₂ = 4(u² / 2a)

s₂ = 4(s₁)

Hence, if you double your driving speed, then the stopping distance will be four times the original.

Learn more about the Equation of Motion here:

https://brainly.com/question/15080570

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